5.00 L Of A Gas Is Known To Contain 0.965 Mol. If The Amount Of Gas Is Increased To 1.80 Mol, What New Volume Will Result ( At An Unchanged Temperatur

5.00 L of a gas is known to contain 0.965 mol. If the amount of gas is increased to 1.80 mol, what new volume will result ( at an unchanged temperature and pressure) ?

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The answer is: 9.326 L volume

This problem can be solved using Avogadros Law in which volume is directly proportional to the amount of gas in moles.

Given Data:

n1 = 1.80 mol                       n2 = 0.965 mol

V1 = 5.00 L                          V2 = ? unknown

Solution:  

We can used the formula n1/V1 = n2/V2

to simplify:

V2 = V1 × n2 / n1

n2 = 5.00 L × 1.80 mol / 0.965 mol

n2 = 9 L / 0.965

n2 = 9.326 L

Hope it helps....=)